Motion Quiz 2
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Question 1 of 16
1. Question
2 pointsA jet plane flying at a speed of 600 km/h is to overtake a biplane which started 3 hours earlier and which is flying at a speed of 400 km/h. How long will it take the faster plane to overtake the slower plane?
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Correct answer 6 hours

Question 2 of 16
2. Question
2 pointsTwo cars started from the same point, at 5 am, traveling in opposite directions at 90 and 110 km/h respectively. At what time will they be 1000 km apart?
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Question 3 of 16
3. Question
2 pointsTwo cars left, at 8 am, from the same point, one travelling east at 65 km/h and the other traveling south at 72 km/h. At what time will they be 485 km apart? A diagram is shown below to help you understand the problem.
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Question 4 of 16
4. Question
2 pointsA car and a bus set out at 2 p.m. from the same point, headed in the same direction. The average speed of the car is 30 км/h slower than twice the speed of the bus. In two hours, the car is 20 км ahead of the bus. Find the rate of the car.
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Let’s assume that the average speed of the bus is X. Then, the average speed of the car is equal to 2X30. The distance L between car and bus in two hours of travelling is L=4X602X. According to the problem L value is equal to 60 km or 4X602X=60. As it is following from this equation the average speed of the bus is X=60 km and the average speed of the car is 2X30=90 km/h.

Question 5 of 16
5. Question
2 pointsTwo cyclists start at the same time from opposite ends of a course that is 140 km long. One cyclist is riding at 15 km/h and the second cyclist is riding at 20 km/h. How long after they begin will they meet?
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The rate of first cyclist is 15 and the rate of the second cyclist is 20. So the distance traveled by the first in time T is 15T and the distance traveled by second cyclist in time T is 20T. The distance traveled by the first and second cyclists together gives us an equation which you can solve for T:
15T + 20T = 140. Solution for T is T=4 hours.

Question 6 of 16
6. Question
2 pointsA bus left city A towards city C. A car left city A half an hour after the bus also towards city C and overtakes a bus at a distance of 50 km from city A. Find the speed of the bus, if it is 50 km/h slower than the speed of the car?
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Question 7 of 16
7. Question
2 pointsA bus left city A to drive at 60 km/h towards city C. A car left city A half an hour after a bus (also towards city C) driving at 80 km/h. How long will it take car to overtake a bus, if the distance between city A and city C is equal to 90 km?
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A bus covers the distance of 90 km in 90/60=1.5 hours. A car has only 1 hour to overtake a bus because car leaves a city A after half an hour (1.50.5). Driving at a rate 80 km/h, a car covers 80 km, which is less than the distance between A and B. Therefore, a car does not overtake a bus on the way between A and B.

Question 8 of 16
8. Question
2 pointsThe passenger of а train moving at a speed of 60 km/h noticed that oncoming freight train that is traveling in the same direction at a speed of 30 km/h, passed him in 10 seconds. What is the length of a freight train?
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Question 9 of 16
9. Question
2 pointsPassenger and freight trains start at the same time from opposite ends of a course that is 1 km long. Passenger train is riding at 90 km/h and the freight train is riding at 60 km/h. How long after they begin will they meet?
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Question 10 of 16
10. Question
2 pointsThe passenger of а train moving at 60 km/h noticed that oncoming freight train that is traveling in opposite direction at a speed of 30 km/h, passed him in 10 seconds. What is the length of a freight train?
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Question 11 of 16
11. Question
2 pointsTwo trains, traveling towards each other, left from two stations that are 192 km apart. First one, left city A towards city B at 7 am, second one left city B towards city A at 8 am. If the rate of the first train is 60 km/h and the rate of the second train is 28 km/h, at what distance from city A will they pass each other?
Please, enter the answer without measurement units, for example, 300, instead 300 km
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Question 12 of 16
12. Question
2 pointsCars travel in same direction in three parallel lanes along highway. Inner lane stream moves at a speed of 90 km/h, center stream – at a speed of 105 km/h, and outer stream rides at a rate 120 km/h. Find the average rate of a car, if it travels during 40 minutes in inner lane, 20 minutes in a central lane and 1 hour in outer lane.
Please, insert an average rate value without measurement units, for example, 50 instead 50 km/h
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Solution : Car travels for 60 km. at a rate 90 km/h in 40 minutes in inner lane, 35 km at a speed of 105 km/h in 20 minutes in central lane and 120 km in an outer lane in 1 hour. So, car covers 215 km in 2 hours. Therefore, an average speed is equal to 107.5 km/h.

Question 13 of 16
13. Question
2 pointsProblem : A man crosses a river with a width of S_{1}=100 m. at a rate of V_{1}=0.25 m/sec with respect to a still water. Speed of a water stream is V_{2}=0.1 m/sec. Find a distance S_{2} man drifts along the water stream.
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Solution : Time to cross a river t is equal to t=S_{1}/V_{1}, therefore, a distance S_{2} man drifts along the water stream is S_{2}=V_{2}×t=V_{2}×S_{1}/V_{1}=0.1×100/0.25=40 m.

Question 14 of 16
14. Question
2 pointsTourists have to travel 95 km in 4 days. Second day they covered 10 km more than the first day, third day they traveled 5 km less than the first day, fourth day they covered the same distance as in the first day. How many kilometers did they travel every day?
A: First day– 20 km, Second day — 30 km, Third day — 25 km, Fourth day — 20 km
B: First day—20 km, Second day — 35 km, Third day — 30 km, Fourth day — 20 km
C: First day—30 km, Second day — 15 km, Third day — 15 km, Fourth day — 30 km
D: First day–10 km, Second day — 40 km, Third day — 35 km, Fourth day — 10 km
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Solution : Let’s say that tourists trip X kilometers first day. Then second day they covered (X+10) km., third day — (X5) km., and fourth day – X km. So, they trip (4X+15)=95 km. in all 4 days. Therefore, they traveled X=20 km. in a first day, 30 km in second day, 25 km. in third day and 20 km. in fourth day.

Question 15 of 16
15. Question
2 pointsProblem : During first two hours cyclist travels North at a rate 15 km/h, next 4 hours he drives East at a speed of 10 km/h and third part of a trip cyclist moves Southwest at a speed of 20 km/h in 2.5 hours. Which graph gives the right route of a cyclist?
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Solution : Cyclist traveled 30 km North during a first part of a trip, next, he covered 40 km East, and by the third stage of the trip he run 50 km Southwest. Values 30, 40 and 50 give three Pythagoras values. So, graph A shows how far cyclist moves in a time.

Question 16 of 16
16. Question
2 pointsTwo cyclists left the same point t the speeds as shown in Figure presented below. The first cyclist headed directly south and the second headed southwest at an angle of 60^{0 }from the path of the first cyclist. What will be the distance between the cyclists in the span of two hours, if the first cyclist is moving at the speed of 10km/h while the second is moving at the speed of 5 km/h?
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